Suppose that 3.03 g of a silver salt ( AgX ) is dissolved in 585.0 mL of water. A current of 2.33 A , applied for 989 s , is required to plate out all of the silver in solution. What is the mass percentage of silver in the salt

Respuesta :

The  mass percentage of silver in the salt is 63.58 %

What is Electrolysis ?

Electrolysis refers to the decomposition of a substance by an electric current.

It is a technique that uses direct electric current (DC) to drive an otherwise non-spontaneous chemical reaction.

Electrolysis is commercially important as a stage in the separation of elements from naturally occurring sources such as ores using an electrolytic cell.    

 

Ag⁺ + e⁻  --> Ag

[tex]\rm W_{Ag} = Z \times I\times t\\\\\\\rm W_{Ag} = \dfrac{Z \times I\times t\\}{96500}\\\\\\W_{Ag} = Mass \; of\; Ag \; plate\\\\\\\rm W_{Ag} = \dfrac{108 \times 2.82\times 695\\}{96500}\\\\\\W_{Ag} = 2.193 g \\\\\\Mass \;percentage\; of \;silver\; in\; salt = \dfrac{mass \;of\;Ag}{Total \;mass\;of\;salt}\times 100\\\\\\\\=\dfrac{2.193}{3.45} \times 100\\\\\\=63.58 \%\\[/tex]

Z = Electrochemical Equivalent.

Z = atomic weight/nF      

n = no. of electron, F = 96500 , Faraday's Constant

Chemical formula of the salt will be determined as

moles of Ag = moles of AgX

[tex]\rm Molecular \; weight \; of \; Ag = 108\\\\\\\rm\dfrac{2.193}{108}= \dfrac{3.45}{M_{AgX}}\\\\\\\\M_{AgX} =170 \;g/mol\\\\\\\\M_{AgX} = M_{Ag} + M_{X}\\\\\\\\170= 108 + M_{X}\\\\\\\\M_{X}= 170-108 = 62\\\\[/tex]

and therefore the salt is AgNO₃ .

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