If the equation of the absolute value function is f(x) = |x + 1| + 7, then the range of the function is -∞ < y ≤ 7
The question is incomplete, so I will provide a general explanation
Assume that the absolute value function is given as:
f(x) = |x + 1| + 7
Set the absolute value to 0
f(x) ≥ 0 + 7
Evaluate
f(x) ≥ 7
This means that the smallest value of the function is 7
Hence, the range of the absolute value function is -∞ < y ≤ 7
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