Question

The height of a toy rocket that is shot in the air with an upward velocity of 48 feet per second can be modeled by the function f (x) = negative 15 t squared 48 t, where t is the time in seconds since the rocket was shot and f(t) is the rocket’s height in feet. what is the maximum height the rocket reaches?

Answer 1

The maximum height of the toy rocket is 38.4 ft, reached 1.6 seconds after it is shot in the air.

How to get the maximum height of the rocket?

We know that the height of the rocket is modeled by:

$f(t) = -15*t^2 + 48t$

Notice that this is a quadratic of negative leading coefficient, which means that the maximum is at the vertex.

Then the maximum is at:

t = -48/(2*-15) = 48/30 = 1.6

This means that the maximum height, in ft, is:

$f(1.6) = -15*(1.6)^2 + 48*1.6 = 38.4$

The maximum height of the toy rocket is 38.4 ft, reached 1.6 seconds after it is shot in the air.

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

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Answer 2

Answer: B, 36 ft

Step-by-step explanation: edge :)