By completing squares, we will see that the solution set of the quadratic equation is {-12, 2}.
Remember the relation:
[tex](a + b)^2 = a^2 + 2ab + b^2[/tex]
Here we start with:
[tex]x^2 + 10x = 24[/tex]
Then, we can rewrite it to get:
[tex]x^2 + 2*5*x = 24[/tex]
Now we can see that a = x and b = 5, then we can add and subtract 5 squared in the left side, so we get:
[tex]x^2 + 2*5*x + 5^2 - 5^2= 24\\\\(x^2 + 2*5*x + 5^2) - 5^2= 24\\\\(x + 5)^2 = 24 + 25 = 49[/tex]
Now we can solve our equation:
[tex](x + 5)^2 = 49\\x + 5 = \pm \sqrt{49} = \pm 7\\x = -5 \pm 7[/tex]
So the solution set is {-12, 2}
If you want to learn more about quadratic equations:
https://brainly.com/question/1214333
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