The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
Given that;
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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