Question

What are the exact values of the six trigonometric functions for negative startfraction 7 pi over 6 endfraction radians? sine (negative startfraction 7 pi over 6 endfraction) = negative startfraction startroot 3 endroot over 2 endfraction; cosine (negative startfraction 7 pi over 6 endfraction) = negative one-half; tangent (negative startfraction 7 pi over 6 endfraction) = negative startroot 3 endroot. cosecant (negative startfraction 7 pi over 6 endfraction) = negative startfraction 2 startroot 3 endroot over 3 endfraction; secant (negative startfraction 7 pi over 6 endfraction) = 2; cotangent (negative startfraction 7 pi over 6 endfraction) = negative startfraction startroot 3 endroot over 3 endfraction sine (negative startfraction 7 pi over 6 endfraction) = negative one-half; cosine (negative startfraction 7 pi over 6 endfraction) = negative startfraction startroot 3 endroot over 2 endfraction; tangent (negative startfraction 7 pi over 6 endfraction) = negative startfraction startroot 3 endroot over 3 endfraction. cosecant (negative startfraction 7 pi over 6 endfraction) = negative 2; secant (negative startfraction 7 pi over 6 endfraction) = negative startfraction 2 startroot 3 endroot over 3 endfraction; cotangent (negative startfraction 7 pi over 6 endfraction) = startroot 3 endroot sine (negative startfraction 7 pi over 6 endfraction) = one-half; cosine (negative startfraction 7 pi over 6 endfraction) = negative startfraction startroot 3 endroot over 2 endfraction; tangent (negative startfraction 7 pi over 6 endfraction) = negative startfraction startroot 3 endroot over 3 endfraction. cosecant (negative startfraction 7 pi over 6 endfraction) = 2; secant (negative startfraction 7 pi over 6 endfraction) = negative startfraction 2 startroot 3 endroot over 3 endfraction; cotangent (negative startfraction 7 pi over 6 endfraction) = negative startroot 3 endroot sine (negative startfraction 7 pi over 6 endfraction) = startfraction startroot 3 endroot over 3 endfraction; cosine (negative startfra

Answer 1

The evaluation of the six trigonometric functions in x = -(7/6)pi can be seen below.

How to evaluate the six trigonometric functions?

We want to evaluate sin(x), cos(x), tan(x), arcos(x), sec(x), arctan(x) in x = -(7/6)pi.

Now we just evaluate the trigonometric functions:

$cos(-\frac{7pi}{6}) = -0.866$

$sin(-\frac{7pi}{6}) = 0.5\\\\tan(-\frac{7pi}{6})) = -0.577\\\\cosec(-\frac{7pi}{6})) = 1/sin(-\frac{7pi}{6}) = 1/0.5 = 2\\\\sec(-\frac{7pi}{6}) = 1/cos(-\frac{7pi}{6}) = -1.155\\\\arctan(-\frac{7pi}{6}) = 1/tan(-\frac{7pi}{6})) = -1.732$

Where for the last 3 we just use the inverse of the first 3 ones.

If you want to learn more about trigonometric equations:

https://brainly.com/question/8120556

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