Question

find the numerical value of the log expression, please help!

Answer 1

Answer:

101

Step-by-step explanation:

$\log a=-8\\\\10^{\log a}=10^{-8}\\\\a=10^{-8}$

$\log b=-9\\\\10^{\log b}=10^{-9}\\\\b=10^{-9}$

$\log c=-9\\\\10^{\log c}=10^{-9}\\\\c=10^{-9}$

$\displaystyle \log\frac{a^2}{b^5c^8}=\log\frac{(10^{-8})^2}{(10^{-9})^5(10^{-9})^8}=\log\frac{10^{-16}}{(10^{-9})^{13}}=\log\frac{10^{-16}}{10^{-117}}=\log(10^{-16-(-117)})=\log(10^{101})=101$