Question

A rocket blasts off and moves straight upward from the launch pad with constant acceleration. After 3.0 s the rocket is at a height of 87 m. Part A What is the magnitude of the rocket's acceleration

Answer 1

Answer:

~19.33m/s^2

Explanation:

$D=v*t-\frac{1}{2}a*t^{2} \\v=0m/s\\D=\frac{1}{2}a*t^{2}\\\frac{D*2}{t^{2} } =a\\\frac{87*2}{3^{2} } =a\\174/9=19.333 m/s^2$