Answer:
terminal point is at (0, -1) and sin 0 = -1
Step-by-step explanation:
In a unit circle the radius of the circle is 1 so
- we know the points where the circle intersects the x-axis and y-axis as a (x , y) coordinates.
(1, 0) where we start on the positive x-axis and where angle is 0°
(0, 1) where we go counterclockwise and where angle is 90°
(-1, 0) where we go continue counterclockwise and where angle is 180°
(0, -1) where we stop in our problem because the angle is 270°
-we also know that x= cos O and y= sin O so the coordinates (x, y) are really
(cos O, sinO)
Given:
0 = 270°
sin 0 = sin 270°
sin 270° = -1
The terminal point is at (0, -1) and sin 0 = -1
