The volume of water needed to prepare the solution given the data is 2.16 L
What is molarity?
This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
How to determine the mole of CaCO₃
- Mass of CaCO₃ = 756 g
- Molar mass of CaCO₃ = 100.1 g/mol
- Mole of CaCO₃ =?
Mole = mass / molar mass
Mole of CaCO₃ = 756 / 100.1
Mole of CaCO₃ = 7.55 moles
How to determine the volume
- Mole of CaCO₃ = 7.55 moles
- Molarity = 3.5 M
- Volume = ?
Volume = mole / molarity
Volume = 7.55 / 3.5
Volume = 2.16 L
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