Question

each day one astronaut exhales about 448 L of carbon dioxide. how many grams of LiOH is needed to remvoe this much carboon dioxide?
CO2(g)+2LiOH(s) to Li2CO3(s)+h2O(1)

Answer 1

Answer:

How to determine the mole of LiOH required to react with 20 moles of CO₂ per day

CO₂ + 2LiOH —> Li₂CO₃ + H₂O

From the balanced equation above,

1 mole of CO₂  required 2 moles of LiOH.

Therefore,

20 moles of CO₂ will require = 20 × 2 = 40 moles of LiOH

How to determine the mole of LiOH required by two astronauts for 3 days

Mole of LiOH for 1 person per day = 40 moles

Mole of LiOH for 2 persons per day = 2 × 40 = 80 moles

Mole of LiOH for 2 persons for 3 days = 80 × 3 = 240 moles

Explanation:

mark brainliest

Answer 2

Any gas at STP weighs 22.4L

Moles of CO_2

• 448/22.4
• 20mol

1 mol CO_2 requires 2 mol LiOH

Moles of LiOH

• 20(2)
• 40mol

Mass of LiOH

• moles ×Molar mass
• 24(40)
• 960g