Question

distance between
P=(0,\ -11) and Q=(0,\ 2)
A=(0,\ 0) and B=(-3,\ -4)
C=(8,\ 0) and D=(0,\ -6)

Answer 1

Answer:

Step-by-step explanation:

distance PQ=√[(0-0)²+(2+11)²]=√13²=13

distance AB=√[(-3-0)²+(-4-0)²]=√(9+16)=√25=√5

distance CD=√[(0-8)²+(-6-0)²]=√(64+36)=√100=10