By applying concepts of linear algebra, the point P'(x, y) = (-3, 4) represents the translation of P(x, y) = (-3, 4) along the vectors <7, -6> and <-1, 3>.
Translations are a kind of rigid transformation. A transformation is rigid if and only if Euclidean distances are conserved. By linear algebra, an image as a consequence of consecutive translations is described by the following formula:
[tex]P' (x,y) = P(x,y) + \left(\sum\limits_{i=1}^{n}x_{i}, \sum\limits_{i=1}^{n}y_{i}\right)[/tex] (1)
Where:
Now we proceed to determine the image of the given point:
P'(x, y) = (-3, 4) + (7, -6) + (-1, 3)
P'(x, y) = (-3 + 7 - 1, 4 - 6 + 3)
P'(x, y) = (3, 1)
By applying concepts of linear algebra, the point P'(x, y) = (-3, 4) represents the translation of P(x, y) = (-3, 4) along the vectors <7, -6> and <-1, 3>.
To learn more on rigid transformations: https://brainly.com/question/1761538
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