Find the area of the circle.
12 ft
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Answer:
Step-by-step explanation:
Given:
To Find:
Using formula:
[tex] \\ \: \: \dashrightarrow \: \: \:{\underline{\boxed{ \bf{Area_{( circle)} = \pi r^2}}}} \\ \\[/tex]
Where,
On substituting the required values, we get:
[tex] \\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 3.14 \times {(6)}^{2} \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 3.14 \times 36 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 113.04 \: {ft}^{2} \\ \\ \\ [/tex]
Hence,
[tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{70}{1}[/tex]
Find the area of the circle (diameter = 12 ft)
[tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}[/tex]
We're asked to find the area of the circle, which can be found using the
following formula:-
[tex]\longmapsto\underline{\boxed{\bold{A=\pi r^2}}}[/tex]
Where:-
Provided Information:-
What to do:-
[tex]\bigstar[/tex] Notice that we have the diameter and not the radius.
[tex]\bigstar[/tex] Since the radius is exactly one-half of the diameter, we divide the
diameter by 2 and get the radius:-
[tex]\longmapsto\sf{d=2r}[/tex]
[tex]\bigstar[/tex] Rearranging the formula,
[tex]\longmapsto\large\text{$r=\displaystyle\frac{d}{2}$}[/tex]
[tex]\bigstar[/tex] Substituting the required value (d=12) in lieu of d:-
[tex]\longmapsto\large\text{r=$\displaystyle\frac{12}{2}$}[/tex]
[tex]\bigstar[/tex] Circle's Radius:-
[tex]\longmapsto\large\text{\boxed{\boxed{r=6}}}[/tex]
[tex]\triangle\rule{300}{1}\triangle[/tex]
Now that we have the radius, let's find the area.
Remember, we need the following formula:-
[tex]\longmapsto\underline{\boxed{\sf{A=\pi r^2}}}[/tex]
[tex]\bigstar[/tex] Substituting the required value (r=6) into the formula,
[tex]\longmapsto\underline{\boxed{\sf{A=\pi (6)^2}}}[/tex]
[tex]\bigstar[/tex] Squaring the radius,
[tex]\longmapsto\underline{\boxed{\sf{A=\pi \times36}}}[/tex]
[tex]\bigstar[/tex] Now, Substitute 3.14 for pi:-
[tex]\longmapsto\sf{A=3.14\times36}[/tex]
[tex]\bigstar[/tex] Multiplying the values,
[tex]\longmapsto\sf{A=113.04\:ft^2}[/tex]
[tex]\longmapsto\Large\underline{\boxed{\text{Option\:D}}}[/tex]
#TogetherWeGoFar
[tex]\rule{300}{1}[/tex]