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A horizontal force of 50.0 N is applied at an angle of 28.5° to a door knob of a 75.0-cm door. What torque is produced to open the door.

Respuesta :

The torque is produced to open the door will be 3295.5 Nm. The amount of torque is equal to force multiplied by the perpendicular distance.

What is torque?

Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force.

The value of torque;

τ=Fdcosθ

τ=50×75.0 ×cos 28.5°

τ=3295.5 Nm

Hence,the torque is produced to open the door will be 3295.5 Nm

To learn more about the torque, refer to the link;

brainly.com/question/6855614

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