The combustion of methane produces carbon dioxide and water. 6230 L of methane will be produced in the reaction.
A combustion reaction is a chemical equation in which the reactant reacts in the presence of oxygen molecules. The combustion reaction of methane is given as:
CH₄ (g)+ 2O₂ (g) → CO₂ (g) + 2 H₂O(g)
From the reaction, it can be said that methane and water are in a ratio of 1: 2.
At STP the volume of water is
10L x 1g/ml x 1ml/0.001L = 1 × 10⁴g of water
Moles of water are:
1 × 10⁴g of water/18g/mole MW of water = 5.56x10² moles of water
From the ratio of methane and water and moles of methane are calculated as:
1/2 x 5.56x10² moles = 2.78x10² moles of methane
The volume of methane is calculated as:
2.78x10² moles of methane x 22.4L/mole = 6.23x10³ L of methane
Therefore, 6230 L of methane is required to produce 10 L of water.
Learn more about combustion reaction here:
https://brainly.com/question/9461700
#SPJ1
