Question

Determine the equation of the line tha has an x-intercept of 4 and a y intercept of-3

Answer 1

Answer:

$y=\frac{3}{4} x-3$

Step-by-step explanation:

Given information: x-int: 4 and y-int:-3

x-int point : (4,0).

y-int point : (0,-3).
Plug this information to point-slope form to solve for m and then convert that to slope-intercept form.

$y-y_0=m(x-x_0)\\0-(-3)=m(4-0)\\3=4m\\m=\frac{3}{4}$

$y-y_0=m(x-x_0)\\y-(-3)=\frac{3}{4} (x-0)\\y+3=\frac{3}{4}x\\y=\frac{3}{4}x-3$