100 points!!!! Which system of equations is represented on the graph?
![100 points Which system of equations is represented on the graph class=](https://us-static.z-dn.net/files/d69/d016dfdcfcca1953514b1abe9373378b.jpeg)
To determine the correct system of equations shown on the graph,
Substitute the coordinates into the slope formula:
[tex]\text{Slope of blue line} = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]\text{Slope of blue line} = \dfrac{4 - 5}{3 - 0}[/tex]
Simplify the expression as needed:
[tex]\text{Slope of blue line} = \dfrac{-1}{3}[/tex]
Therefore, the slope of the blue line is -1/3.
The point of the blue line that is intersecting the y-axis is (0, 5).
Therefore, the y-intercept of the blue line is 5.
Slope intercept form: y = mx + b
[Where "m" is the slope and "b" is the y-intercept]
⇒ [tex]y = (m)x + (b)[/tex]
⇒ [tex]y = (\frac{-1}{3} )x + (5)[/tex]
⇒ [tex]y = \frac{-1}{3}x + 5[/tex]
Therefore, the equation of the blue line is y = -1/3x + 5
Choosing any two points on the red line:
Substitute the coordinates into the slope formula:
[tex]\text{Slope of red line} = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]\text{Slope of red line} = \dfrac{0 - (-2)}{1 - 0}[/tex]
Simplify the expression as needed:
[tex]\text{Slope of red line} = \dfrac{2}{1} = 2[/tex]
Therefore, the slope of the red line is 2.
The point of the red line that is intersecting the y-axis is (0, -2).
Therefore, the y-intercept of the red line is -2.
Slope intercept form: y = mx + b
[Where "m" is the slope and "b" is the y-intercept]
⇒ [tex]y = (m)x + (b)[/tex]
⇒ [tex]y = (2 )x + (-2)[/tex]
⇒ [tex]y = 2x - 2[/tex]
Therefore, the equation of the red line is y = 2x - 2
y = 2x - 2 and y = -1/3x + 5 ======> Option A