Respuesta :

To determine the correct system of equations shown on the graph,

  1. Choose any two points on the line.
  2. Determine the x and y coordinates of all points
  3. Determine the slope of the line
  4. Determine the y-intercept of the line.
  5. Plug the slope and the y-intercept in the slope intercept form.

Determining the equation of the blue line

Choosing any two points on the blue line:

  • Chosen points on blue line: (0, 5) and (3, 4)

Determining the coordinates of the two points:

  • y-coordinate of second point = y₂ = 4
  • y-coordinate of first point = y₁ = 5
  • x-coordinate of second point = x₂ = 3
  • x-coordinate of first point = x₁ = 0

Determining the slope of the line:

Substitute the coordinates into the slope formula:

[tex]\text{Slope of blue line} = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]\text{Slope of blue line} = \dfrac{4 - 5}{3 - 0}[/tex]

Simplify the expression as needed:

[tex]\text{Slope of blue line} = \dfrac{-1}{3}[/tex]

Therefore, the slope of the blue line is -1/3.

Determining the y-intercept of the line:

The point of the blue line that is intersecting the y-axis is (0, 5).

Therefore, the y-intercept of the blue line is 5.

Plug the slope and the y-intercept in the slope intercept form.

Slope intercept form: y = mx + b

[Where "m" is the slope and "b" is the y-intercept]

⇒ [tex]y = (m)x + (b)[/tex]

⇒ [tex]y = (\frac{-1}{3} )x + (5)[/tex]

⇒ [tex]y = \frac{-1}{3}x + 5[/tex]

Therefore, the equation of the blue line is y = -1/3x + 5

Determining the equation of the red line:

Choosing any two points on the red line:

  • Chosen points on red line: (0, -2) and (1, 0)

Determining the coordinates of the two points:

  • y-coordinate of second point = y₂ = 0
  • y-coordinate of first point = y₁ = -2
  • x-coordinate of second point = x₂ = 1
  • x-coordinate of first point = x₁ = 0

Determining the slope of the line:

Substitute the coordinates into the slope formula:

[tex]\text{Slope of red line} = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]\text{Slope of red line} = \dfrac{0 - (-2)}{1 - 0}[/tex]

Simplify the expression as needed:

[tex]\text{Slope of red line} = \dfrac{2}{1} = 2[/tex]

Therefore, the slope of the red line is 2.

Determining the y-intercept of the line:

The point of the red line that is intersecting the y-axis is (0, -2).

Therefore, the y-intercept of the red line is -2.

Plug the slope and the y-intercept in the slope intercept form.

Slope intercept form: y = mx + b

[Where "m" is the slope and "b" is the y-intercept]

⇒ [tex]y = (m)x + (b)[/tex]

⇒ [tex]y = (2 )x + (-2)[/tex]

⇒ [tex]y = 2x - 2[/tex]

Therefore, the equation of the red line is y = 2x - 2

Final answer:

y = 2x - 2 and y = -1/3x + 5 ======> Option A