Answer:
0.0734 grams LiOH
Explanation:
The molarity formula looks like this:
Molarity (M) = moles / volume (L)
You are given the molarity and volume (in mL). Therefore, you can plug these values into the equation and solve for moles (after you convert from mL to L).
25 mL / 1,000 = 0.025 L
0.125 M = moles / 0.025 L
(0.125 M) x (0.025 L) = moles
0.003125 = moles
After using the molarity formula, we know that 0.003125 moles LiOH are needed to satisfy these conditions. Now, we can convert this to grams using the molar mass of LiOH. This can be determined using the values from the periodic table. Remember to write your conversion in a way that allows for the units to cancel out.
Molar Mass (LiOH) = 6.941 g/mol + 16.00 g/mol + 1.008 g/mol
Molar Mass (LiOH) = 23.499 g/mol
0.003125 moles 23.499 g
------------------------ x ------------------- = 0.0734 grams LiOH
1 mole
