Question

A bullet of mass 0.045 kg is travelling horizontally at 400 m/s when it strikes a stationary wooden block of mass 16 kg. The bullet is embedded in the block. Calculate the speed of the block with the bullet embedded within.

Velocity: m/s

Answer 1

Answer:9.17 m|s

Explanation:

explanation shown

Answer 2

Apply conservation of momentum

$\\ \rm\Rrightarrow m1v1+m2v2=(m1+M2)v3$

$\\ \rm\Rrightarrow 0.045(400)+16(0)=(0.045+16)V3$

$\\ \rm\Rrightarrow 18=16.045v3$

$\\ \rm\Rrightarrow v3=1.12m/s$