Answer:
[tex]\frac{2x^2+4x-9}{(2x-3)(2x+3)(x-1)}[/tex]
Step-by-step explanation:
[tex]\frac{2x}{4x^2-9} + \frac{3}{2x^2+x-3}[/tex] can be simplified to:
[tex]\frac{2x}{(2x-3)(2x+3)}+\frac{3}{(2x+3)(x-1)}[/tex]
Make them have common denominators so:
[tex]\frac{(2x)(x-1) +3(2x-3)}{(2x-3)(2x+3)(x-1)}[/tex]
Simplify:
[tex]\frac{2x^2-2x+6x-9}{(2x-3)(2x+3)(x-1)} = \frac{2x^2+4x-9}{(2x-3)(2x+3)(x-1)}[/tex]
I don't think you can simplify that fraction further so that's the answer.
