The perimeter of the rectangle will be given by the equation 2(x₂-x₁)+2(y₂-y₁).
The perimeter is defined as the sum of all the sides of the figure. Here in the question, we have the rectangle with coordinates (x₁,y₁),(x₂,y₂),(x₂,y₁)(x₂,y₂).
So by using the distance formula we will find the length and width of the rectangle.
[tex]l=\sqrt{x_2-x_1)^2+(y_1-y_1)^2}[/tex]
[tex]l=\sqrt{(x_2-x_1)^2}[/tex]
l=x₂-x₁
Width of the rectangle is given by
[tex]w=\sqrt{x_2-x_2)^2+(y_1-y_1)^2}[/tex]
[tex]w=\sqrt{(y_2-y_1)^2}[/tex]
w=(y₂-y₁)
Hence, the perimeter of the rectangle is given by
P=2l+2w
P=2(x₂-x₁)+2(y₂-y₁)
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