Answer:
[tex]\displaystyle x=\frac{7\pm\sqrt{37}}{6}[/tex]
Step-by-step explanation:
[tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\frac{-(-7)\pm\sqrt{(-7)^2-4(3)(1)}}{2(3)}\\\\x=\frac{7\pm\sqrt{49-12}}{6}\\ \\x=\frac{7\pm\sqrt{37}}{6}[/tex]