Question

What is limit of (sine (startfraction pi x over 6 endfraction) ) as x approaches negative 1? negative startfraction startroot 3 endroot over 2 endfraction negative one-half one-half startfraction startroot 3 endroot over 2 endfraction

Answer 1

The limit of $sin(\frac{\pi x}{6} )$ as x approaches negative 1 is determined as negative half (- ¹/₂).

What is the limit of the function?

The limit of the sine function is calculated as follows;

$\lim[sin(\frac{\pi x}{6} )]_ {x\to -1}$

Substitute the value of x into the above equation;

= sin(-π/6)

= sin(-180/6)

= sin(-30)

= - sin(30)

= - ¹/₂

Thus, the limit of $sin(\frac{\pi x}{6} )$ as x approaches negative 1 is determined as negative half (- ¹/₂).

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