A sample of argon has a volume of 0.43 ml at 299k. The temperature is 695 K.
The ideal gas law tells the macroscopic properties of the gas. The particles of the gas does not repel or attract to each other.
Given, the volume 1 is 0.43
Pressure1 is 299 k
volume 2 is 1ml
Putting the value in the equation
[tex]\dfrac{V_1}{T_1 } =\dfrac{V_2}{T_2} \\\\\dfrac{0.43}{299} =\dfrac{1}{T_2} = 695.43 \\[/tex]
Thus, the temperature is 695 K.
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