Respuesta :

[tex]\\ \rm\Rrightarrow (2x^2)^3.2yx^0=8x^6.2y=16x^6y[/tex]

[tex]\\ \rm\Rrightarrow (2x^4y^3)^3.2x^4y^4=8x^{12}y^6.2x^4y^4=16x^{16}y^{10}[/tex]

[tex]\\ \rm\Rrightarrow (m^3n^0(2m^3n^2)^4)^2=(m^316m^{12}n^8)^2=(16m^{15}n^8)^2=256m^{30}n^{16}[/tex]

[tex]\\ \rm\Rrightarrow (2xy^3)^2.2x^2y^0=4x^2y^6.2x^2=8x^4y^6[/tex]

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