The quadrilateral is a trapezoid and the area of the quadrilateral is 85.04 square units
How to determine the quadrilateral?
The vertices are given as:
A:(-2, 3) B:(4, -6) C:(10, 2) D:(6, 8)
Next, we plot the vertices (see attachment)
From the attached graph, we can see that the quadrilateral is a trapezoid
How to determine the area?
From the plot, we have the following features:
Height: AD
Parallel sides: CD and AB
Calculate the lengths using:
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}[/tex]
So, we have:
[tex]AD = \sqrt{(-2 -6)^2 + (3 -8)^2}[/tex]
[tex]AD = \sqrt{89}[/tex]
[tex]CD = \sqrt{(10 -6)^2 + (2 -8)^2}[/tex]
[tex]CD = \sqrt{52}[/tex]
[tex]AB = \sqrt{(-2 -4)^2 + (3 +6)^2}[/tex]
[tex]AB = \sqrt{117}[/tex]
The area is then calculated as:
Area = 0.5 * (CD + AB) * AD
This gives
Area = 0.5 * (√52 + √117) * √89
Evaluate
Area = 85.04
Hence, the area of the quadrilateral is 85.04 square units
Read more about areas at:
https://brainly.com/question/24487155
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