Question:
Rectangle A has area of 40cm² and length 8cm. The area of rectangle B is one-half the area of rectangle A. The rectangle have the same length. What is the width of rectangle B ?
Answer:
Given:
- Area of Rectangle B is half of the area of Rectangle A.
[tex] \quad [/tex][tex] \quad [/tex] [tex] \quad [/tex] [tex] \quad [/tex][tex]{\large{\rm{{ \frac{1}{2} \times 40{cm}^{2} = 20{cm}^{2}}}}}[/tex]
- Length of both the rectangles are same.
[tex] \quad [/tex]
Rectangle A :-
- Length (l) = 8 cm
- Area (A) = 40cm²
Rectangle B :-
- Length (l) = 8cm
- Area (A) = 20cm²
Width :
[tex] \quad [/tex] [tex] \quad [/tex] [tex] { \large{ \sf {\frac{Area (A)}{Length (L)}}}} \longrightarrow \frac{{ \cancel{20}}^{5} }{{ \cancel{8}} ^{2}} = \frac{5}{2} [/tex]
Thus, Width of Rectangle B is 5/2 cm.
[tex] \: [/tex]
[tex] \: [/tex]
Check:
We know,
[tex] \quad [/tex] Area of Rectangle = length × breadth
➛ 8 × [tex] \frac{5}{2} [/tex]
➛ [tex] {\large{ \frac{40}{2}}} [/tex]
➛ [tex] {\large{ \frac{ \cancel{40}^{20} }{ \cancel{2}^{1} }} = { \boxed{ \red{20}}}} [/tex]
