Answer:
y = x² + 5x - 14
Step-by-step explanation:
If the zeros of a polynomial are 2 and -7, then:
⇒ x = 2 ⇒ (x - 2) = 0
⇒ x = -7 ⇒ (x + 7) = 0
Therefore, we can write the polynomial as:
y = a(x - 2)(x + 7) where a is some constant
As the first term of the given polynomial is x², we can say that its coefficient is 1. Therefore, a = 1
⇒ y = 1(x - 2)(x + 7)
⇒ y = (x - 2)(x + 7)
To write the polynomial in standard form ax² + bx + c
simply expand the brackets:
⇒ y = (x - 2)(x + 7)
⇒ y = x² + 7x - 2x - 14
⇒ y = x² + 5x - 14
