Question

Goblin gryh can count the coins in a bag in 10 minutes. of goblin Birt counts with him, they can count all the coins in 6 minutes. How long would it take goblin Birt to count the coins in the bag by himself?

Answer 1

Answer:

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Answer 2

Goblin Birt can take 15 minutes to count the coins in the bag by himself.

What is unitary mehtod?

The unitary method is a process for solving a problem by first finding the value of a unit, and then finding the necessary value by multiplying the single unit value.

How to calculate how long would it take goblin Birt to count the coins in the bag by himself ?

• In this problem, unitary method is to be applied three times.
• Here, counting all the coins is considered as the entire work which is considered as 1.

According to the problem,

• Goblin gryh can count the coins in a bag in 10 minutes.

∴ In 10 minutes Goblin gryh can count the coins in the bag.

∴ In 1 minute Goblin gryh can count $\frac{1}{10}$ th part of the coins in the bag.

Again, according to the problem,

• Goblin gryh and Goblin Birt both can count all the coins in 6 minutes.

∴ In 6 minutes, Goblin gryh and Goblin Birt both can count all the coins in the bag

∴ In 1 minute, Goblin gryh and goblin Birt both can count $\frac{1}{6}$ th  part of the coins in the bag.

∴ In 1 minute, Goblin Birt can count $(\frac{1}{6} - \frac{1}{10})$ th part of the coins in the bag.

                                             = $\frac{5-3}{30} = \frac{2}{30} = \frac{1}{15}$ th part of the coins.

∴ We can say,

Goblin Birt can count $\frac{1}{15}$ th part of the coins in the bag in 1 minute.

∴ Goblin Birt himself can count all the coins in the bag in 15 minutes.

Find out more information about calculation by unitary method here:

https://brainly.com/question/24587372

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