Question

How many moles is 8.7 x 1027 atoms of Helium?

Answer 1

Answer:

14500.

Explanation:

1) Avlgadro's number is 6.022*10²³;

2) 1 mol is 6.022*10²³ atoms of Hellium, then 8.7*10²⁷ atoms is

$3) \ \frac{87*10^{26}}{6*10^{23}}=14.5*10^3=14500[moles].$