Question

A seesaw has a plank of 4.5 m long which is supported by a pivot at its center and moves in a vertical plane above the pivot. If the height of the pivot pillar above the ground is 1 m, through what maximum angle can the seesaw beam move?

Answer 1

Since the pivot pillar is 1 m above the ground, maximum angle can the seesaw beam move is 26.39°

The maximum angle can be gotten using trigonometric ratios answer the question,

What are trigonometric ratios?

Trigonometric ratios are the ratios of the sides of a triangle.

What are angles?

Angles are a measure of rotation or bearing.

Given that the seesaw plank is 4.5 m long and the pivot pillar is 1 m above the ground, when the seesaw is at maximum angle, it forms a right angled triangle with the ground.

It also forms a smaller similar triangle with the same maximum angle Ф which is gotten from the trigonometric ratio

sinФ = h/L where

• h = height of pivot pillar above ground = 1 m and
• L = length of midpoint of plank = 4.5m/2 = 2.25 m

Maximum angle seesaw beam can move

So, Ф = sin⁻¹(h/L)

= sin⁻¹(1 m/2.25 m)

= sin⁻¹(1/2.25)

= sin⁻¹(0.4444)

= 26.39°

So, maximum angle can the seesaw beam move is 26.39°

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