Question

How many grams of H2O will be produced if 750. grams of Fe are produced?
Fe3O4 + 4H2 - 3Fe + 4H20​

Answer 1

Answer:

$\boxed{\small \sf \: Mass \: of \: H_2O =322.2 \: grams}$

Explanation:

Given:

Mass of ferous (Fe) produced = 750 gram.

To find:

Mass of water produced= ?

Solution:

Molar mass of Fe is 55.84 gram/mol

Let's find out the number of moles of ferous produced.

$\small \sf Number \: of \: moles = \frac{Given \: mass \: of \: substance }{Molar \: mass \: of \: substance}$

Substituting the given data in above formula.

$\small \sf Number \: of \: moles = \frac{750}{55.84}$

$\boxed{\small \sf Number \: of \: moles \: of \: Fe= 13.43 \: moles}$

Now the given reaction is,

$Fe_3O_4 + 4H_2 \rightarrow 3Fe + 4H_2O$

• For every 3 mole of production of Fe, 4 mole of waters are produced.
• let for 13.43 moles of Fe x moles of H2O will be produced.

now calculate the number of moles of H2O

$\sf \: \frac{3}{4} = \frac{13.43}{x} \\ \sf x = \frac{13.43 \times 4}{3} \\ \sf x = 17.90 \: moles$

$\small \boxed{\sf number \: of \: moles \: of \: H_2O= 17.90 \: moles}$

mass of one mole of H2O is 18 gram, so we can calculate mass of 17.90 moles.

$\small \sf \: Mass \: of \: H_2O = 17.90 \times 18 \\ \boxed{\small \sf \: Mass \: of \: H_2O =322.2 \: grams}$

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