6.99 grams of iron (Fe) would produce 10 g of rust (Fe2O3) when iron combines with oxygen to form rust.
How to calculate mass?
The mass of a substance can be calculated as follows:
According to this question, iron combines with oxygen to form rust as follows:
4Fe + 3O2 → 2Fe2O3
First, we convert the mass of rust to moles as follows:
moles of Fe2O3 = 10g/159.69 = 0.063moles
- 4 moles of Fe produces 2 moles of Fe2O3
- 0.063 moles of Fe2O3 will be produced by 0.125 moles of Fe.
Next, convert moles of Fe to mass as follows:
mass of Fe = 0.125 × 55.85 = 6.99g
Therefore, 6.99 grams of iron (Fe) would produce 10 g of rust (Fe2O3) when iron combines with oxygen to form rust.
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