Question

A basketball is shot into the air. Its height is represented by the polynomial equation
h(t) = -162 + 35t + 5, where h is the height of the basketball at t seconds. What is
the height of the basketball at 1 second?
A) 56 feet
B) 24 feet
C) 14 feet
D) 8 feet

Answer 1

Answer:

B) 24 feet

General Formulas and Concepts:
Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

Functions

• Function Notation

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle h(t) = -16t^2 + 35t + 5$

Step 2: Find Height

Since we are trying to find the height of the basketball at 1 second, it implies that t = 1. Therefore, we can simply substitute t = 1 into our function:

$\displaystyle\begin{aligned}h(1) & = -16(1)^2 + 35(1) + 5 \\& = -16(1) + 35(1) + 5 \\& = -16 + 35 + 5 \\& = \boxed{24} \\\end{aligned}$

∴ the height of the basketball at 1 second is equal to 24 feet.

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Topic: Algebra I