Respuesta :
Answer:
From the mole ratio of the gases, 10 moles of hydrogen will produce 10 moles of water, and if 10.0 L of hydrogen and 6.0 L of oxygen were used, 10.0 L of water will be produced.
What is the mole ratio of reactants in the formation of water?
The mole ratio of the reactants in the formation of water can be shown from the equation below:
Mole ratio of hydrogen to oxygen is 2:1
10 moles of hydrogen will require 5 moles of oxygen, therefore hydrogen is the limiting reactant.
10 moles of hydrogen will produce 10 moles of water.
1 mole of a gas has a volume of 22.4 L.
If 10.0 L of hydrogen and 6.0 L of oxygen were used, 10.0 L of water will be produced.
Therefore, the volume ratio of gas equals mole ratio of gas
Explanation:
Answer: 192g O2
Explanation:
Balanced equation
S + O2 → SO2
1mol O2 produces 1 mol SO2
6mol O2 required to produce 6 mol SO2
Molar mass O2 = 32g/mol
Mass of 6 mol O2 = 6*32 = 192g O2 required.