Question

How many moles of gas are in a 30-liter scuba canister if the temperature of the canister is 300 K and the pressure is 15,200 torr?

Answer 1

Answer:

n = 0.487⋅mol

Explanation

n=PVRT

=0.4⋅atm×30⋅L0.0821⋅L⋅atm⋅K−

1⋅mol−1×300⋅K

=0.487⋅mol