The width and the length of the rectangular pen will be equal to w=11 feet and the length=20 feet.
The perimeter is defined as the sum of all the sides of the figure. In a rectangle, it is the sum of all the sides of the rectangle.
For this problem, we need to find what perimeter is equal to 62 feet. To find the perimeter of a rectangle we do:
P=2w+2l
where p = perimeter, w = width, and l = length
This problem says that the length is 9 feet longer than the width, so the length would be:
w+9
Now we know what the perimeter and length is, so we can put those into the equation above. This is what it will look like:
62=2w+2(w+9)
and that will solve like so:
62=2w+2w+18
62=4w+18
44=4w
w=11
Now that we know the width we can plug it into our first equation to find the length:
62=(2(11)+2l
62=22+2l
40=2l
l=20
Your width is 11 feet and your length is 20 feet.
hence the width and the length of the rectangular pen will be equal to w=11 feet and the length=20 feet.
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