Question

The table shows the results of rolling a number cube with sides labeled 1 through 6 several times.

What is the experimental probability of rolling a 3 or a 6?

Enter your answer as a fraction in simplest form in the box.
1 10
2 6
3 4
4 8
5 6
6 6

Answer 1

Total times die rolled =10+6+4+8+6+6=40

Times 3 and 6 appears

• 4+6=10

Experimental probability

P(3 or 6)

• 10/40
• 1/4
• 0.25

Answer 2

Answer:

$\sf \dfrac{1}{4}$

Step-by-step explanation:

Experimental probability

Calculated by dividing the number of times an event happens by the total number of trials in an actual experiment.

$\textsf{Experimental Probability} = \dfrac{\textsf{Number of times an event happens}}{\textsf{Total number of trials}}$

Total number of trials = 10 + 6 + 4 + 8 + 6 + 6 = 40

Total number of times rolling a 3 or a 6 = 4 + 6 = 10

$\textsf{Experimental Probability of rolling 3 or 6} = \sf \dfrac{10}{4}=\dfrac{1}{4}$