Question

Water has a specific heat of 4.184 J/g°C and requires 23,000 J of heat to raise the
temperature 68° C. What is the mass of the water?

Answer 1

Answer:

$m=80.840 kg$

Step-by-step explanation:

Given Data,

Q=23000 J

c=4.184 J/g °c

Δt= 68 °c

m=?

By using this equation,

Q=mcΔt

$23000=m\times 4.184\times 68\\\\m=\frac{23000}{4.184\times68} \\\\\\m=80.840 kg$