Respuesta :
Answer: 6
Step-by-Step Explanation:
We first Solve for ‘x’ :-
=> 5(3x - 1) = 55
= 15x - 5 = 55
= 15x = 55 + 5 = 60
=> x = 60/15 = 4
Therefore, x = 4
We can now Substitute the value of ‘x’ in 2x - 2 to find the value :-
= 2x - 2
= 2(4) - 2
= 8 - 2
= 6
Therefore, 2x - 2 = 6 (as x = 4)
Step-by-Step Explanation:
We first Solve for ‘x’ :-
=> 5(3x - 1) = 55
= 15x - 5 = 55
= 15x = 55 + 5 = 60
=> x = 60/15 = 4
Therefore, x = 4
We can now Substitute the value of ‘x’ in 2x - 2 to find the value :-
= 2x - 2
= 2(4) - 2
= 8 - 2
= 6
Therefore, 2x - 2 = 6 (as x = 4)
Hey ! there
Answer:
- Value of 2x - 2 is 6 .
Step-by-step explanation:
In this question we are provided with an equation that is 5 ( 3x - 1 ) = 55 and we are asked to find the value of 2x - 2 .
Firstly , we need to find the value of x . So we need to solve the equation .
SOLUTION : -
[tex] \quad \longmapsto \qquad \: 5(3x - 1) = 55[/tex]
Step 1 : Dividing with 5 on both sides :
[tex] \quad \longmapsto \qquad \: \dfrac{ \cancel{5}(3x - 1)}{ \cancel{5}} = \cancel{\dfrac{55}{5} }[/tex]
On cancelling , We get :
[tex] \quad \longmapsto \qquad \:3x - 1 = 11[/tex]
Step 2 : Adding 1 on both sides :
[tex] \quad \longmapsto \qquad \:3x - \cancel{1} + \cancel{1} = 11 + 1[/tex]
On simplifying , We get :
[tex] \quad \longmapsto \qquad \:3x = 12[/tex]
Step 3 : Dividing with 3 on both sides :
[tex] \quad \longmapsto \qquad \: \dfrac{ \cancel{3}x}{ \cancel{3}} = \cancel{ \dfrac{12}{3} }[/tex]
We get ,
[tex] \quad \longmapsto \qquad \: \underline{\boxed{\frak{x = 4}}}[/tex]
→ Therefore , value of x is 4 .
Verifying : -
Now we are verifying whether our answer is wrong or right . So ,
- 5 ( 3x - 1 ) = 55
- 5 { 3( 4 ) - 1 } = 55
- 5 ( 12 - 1 ) = 55
- 5 ( 11 ) = 55
- L.H.S = R.H.S
- Hence , Verified .
Therefore , our value of x is correct/valid .
We need to find the value of 2x - 2 .
[tex] \quad \longmapsto \qquad \:2x - 2[/tex]
So substituting value of x in it :
[tex]\quad \longmapsto \qquad \:2( \bold{4}) - 2[/tex]
Multiplying 2 with 4 :
[tex]\quad \longmapsto \qquad \:8 - 2[/tex]
Subtracting 2 from 8 :
[tex]\quad \longmapsto \qquad \: \blue{\underline{\boxed{\frak{6}}}} \quad \: \bigstar[/tex]
- Henceforth, value of 2x - 2 is ❝ 6 ❞.