Using an exponential function, it is found that it takes 5.42 years for the car to halve in value.
A decaying exponential function is modeled by:
[tex]A(t) = A(0)(1 - r)^t[/tex]
In which:
In this problem, the car depreciates 12% a year in value, hence r = 0.12 and the equation is given by:
[tex]A(t) = A(0)(0.88)^t[/tex].
It halves in value at t years, for which A(t) = 0.5A(0), hence:
[tex]A(t) = A(0)(0.88)^t[/tex]
[tex]0.5A(0) = A(0)(0.88)^t[/tex]
[tex](0.88)^t = 0.5[/tex]
[tex]\log{(0.88)^t} = \log{0.5}[/tex]
[tex]t\log{0.88} = \log{0.5}[/tex]
[tex]t = \frac{\log{0.5}}{\log{0.88}}[/tex]
t = 5.42.
It takes 5.42 years for the car to halve in value.
More can be learned about exponential functions at https://brainly.com/question/25537936
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