Question

solve for x ~

$\bold\pink{x {}^{2} + 5x - 6 = 0}$

ty! ._.

Answer 1

$\qquad \qquad \rm \large \dag \: Answer \: \dag$

We have been given a Quadratic equation, where we have to find the real values of x ~

So, let's proceed with middle term splitting method :

$\qquad \sf  \dashrightarrow \: {x}^{2} + 5x - 6 = 0$

$\qquad \sf  \dashrightarrow \: x {}^{2} + 6x - x - 6 = 0$

$\qquad \sf  \dashrightarrow \: {x(}^{} x + 6) - 1(x + 6) = 0$

$\qquad \sf  \dashrightarrow \: (x + 6)(x - 1) = 0$

Now, we have two conditions here~

Either (x + 6) = 0

$\qquad \sf  \dashrightarrow \: x = - 6$

or (x - 1) = 0

$\qquad \sf  \dashrightarrow \: x = 1$