Question

Which is the equation of a trend line that passes through the points (7, 450) and (14, 401)? y = negative 7 x 499 y = negative startfraction 1 over 7 endfraction x 451 y = startfraction 1 over 7 endfraction x 449 y = 7 x 401

Answer 1

The equation of the line that passes through the points (7, 450) and (14, 401) is y + 7x = 499

How to find equation of a line?

The equation of a line  can be represented as follows:

y - y₁ = m(x - x₁)

where

• m = slope

Therefore, (7, 450)(14, 401)

m = 401 - 450 / 14 - 7 = -49 / 7 = -7

Therefore, using (7, 450)

y - 450 = -7(x - 7)

y - 450 = -7x + 49

y + 7x = 49 + 450

y + 7x = 499

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