Respuesta :
The solution of the rational equation [tex]\frac{3}{a + 2} * \frac{2}{a} = \frac{4 a - 4 }{a^2 - 4}[/tex] is a = 3
How to determine the solution?
The equation is given as:
[tex]\frac{3}{a + 2} * \frac{2}{a} = \frac{4 a - 4 }{a^2 - 4}[/tex]
Express a^2 - 4 as  a difference of two squares
[tex]\frac{3}{a + 2} * \frac{2}{a} = \frac{4 a - 4 }{(a + 2)(a - 2)}[/tex]
Cancel out the common terms
[tex]\frac{3}{} * \frac{2}{a} = \frac{4 a - 4 }{a - 2}[/tex]
Factor out 2 from 4a - 4
[tex]\frac{3}{} * \frac{2}{a} = \frac{2(a - 2) }{a - 2}[/tex]
Evaluate the quotient
[tex]\frac{3}{} * \frac{2}{a} = 2[/tex]
Divide both sides by 2
[tex]\frac{3}{1} * \frac{1}{a} = 1[/tex]
Cross multiply
a = 3
Hence, the solution of the equation [tex]\frac{3}{a + 2} * \frac{2}{a} = \frac{4 a - 4 }{a^2 - 4}[/tex] is 3
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Answer:
the answer for Which solution to the equation StartFraction 3 Over a + 2 EndFraction + StartFraction 2 Over a EndFraction = StartFraction 4 a minus 4 Over a squared minus 4 EndFraction is EXTRANEOUS? is a: a=-2
Step-by-step explanation: