Answer: [tex]1.0535 \times 10^{24} \text{ molecules of manganese}[/tex]
The result is approximate.
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Work Shown:
[tex]1.75 \text{ moles} \times \frac{6.02 \times 10^{23} \text{ molecules}}{1 \text{ mole}}\\\\(1.75 \times 6.02) \times 10^{23} \text{ molecules}\\\\(10.535) \times 10^{23} \text{ molecules}\\\\(1.0535 \times 10^1) \times 10^{23} \text{ molecules}\\\\1.0535 \times (10^1 \times 10^{23}) \text{ molecules}\\\\1.0535 \times 10^{1+23} \text{ molecules}\\\\1.0535 \times 10^{24} \text{ molecules}\\\\[/tex]
Note: In the second step, the "mole" units cancel when dividing.
