Question

PLEASE HELP ASAP !!

A particle moves in a a straight line along the x-axis. Its displacement (distance from 0 along the x-axis) is given by the following equation: f(t) = 3(t)^4 - 5(t)^3 + 6(t) - 7; t >= 0, where t is measured in seconds and f is measured in meters. Find the velocity of the function after 2 seconds.

Answer 1

The velocity of a particle when it moves on a straight line along the x-axis will be V= 42 m/s

What is velocity?

Velocity is defined as the ratio of the distance moved by the object in a particular time. The velocity is a vector quantity so it needs both the magnitude and the direction.  

Here we have a displacement function:-

F(t)=3t⁴-5t³+6t-7

So to find out the velocity we will differentiate the above equation with respect to t.

d(F(t)/dt=12t³-15t²+6

V=12t³-15t²+6

Put the value of t=2 seconds

V=12x(2x2x2)-15x(2x2)+6

V=42 meters per second

Hence the velocity of a particle when it moves on a straight line along the x-axis will be V= 42 m/s

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