Question

A 40-kilogram mass is moving across a horizontal surface at 5.0 m/s. what is the magnitude of the net force required to bring the mass to a stop in 8.0 seconds?

Answer 1

Answer:

25 N

Explanation:

Use the equation F = m(Vf–Vi) / Δt.

average force = mass (final velocity - initial velocity) / change in time

F = 40 kg(5.0 m/s) / 8.0 s = 200 / 8.0 = 25 kgm / s^2 = 25 Newtons