The surface area of the solid will be A=327.5 square inches and the lateral surface area will be A= 377.5 square inches.
The space occupied by any figure in the two-dimensional space is called an area. The area can be rectangular circular triangular types.
Here we have the figure made up by the two pyramids and one rectangular box. So we will find the surface area of the pyramid then the rectangular box and again the pyramid and will add all of them.
The Lateral surface area will be calculated as:-
A=2W√(w÷2)²+(h)²+w²
A=2x5√(5÷2)²+(3)²+5x5
A=152.5 +25
A=177.5 square inch
Area of lower pyramid= (1÷2)xbxh+w²
A=(1÷2)x5x7.5 + 25 =75+25= 100
Area of the rectangular box= 4(w²)=4(5x5)=100
So total lateral surface area will be =100+100+177.5=377.5 square inch
(2)The surface area will be calculated as:-
A=2W√(w÷2)²+(h)²
A=2x5√(5÷2)²+(3)²
A=152.5 square inches
Area of lower pyramid= (1÷2)xbxh
A=(1÷2)x5x7.5 =75 square inches
Area of the rectangular box= 4(w²)=4(5x5)=100
So total surface area will be =100+75+152.5=327.5 square inch
Hence the surface area of the solid will be A=327.5 square inches and the lateral surface area will be A= 377.5 square inches.
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