Question

A rectangle has an area of 4y2 – 49 square
units. What are the dimensions of the
rectangle?

Answer 1

Answer:

D. (2y - 7) units by (2y + 7) units

Step-by-step explanation:

• $A(rectangle) =4y^2-49$

• $\implies A(rectangle) =(2y)^2-(7)^2$

• $\implies A(rectangle) =(2y-7)(2y+7)$

• -> D(rectangle) = (2y-7) units by (2y + 7) units